Load voltage formula: the quick answer

Voltage drop (Vd) = 2 × K × I × L ÷ CM. Voltage-drop percentage = Vd ÷ source voltage × 100. Load voltage = source voltage − Vd.
(Key equation)

K is the conductor-material constant, I is current in amperes, L is the one-way source-to-load distance and CM is conductor area in circular mils. Do not double L before using this formula; the factor of 2 already represents the outgoing and return path.

How do you calculate voltage drop?

Every metallic conductor has internal electrical resistance. As current flows through a run of copper or aluminum wire, part of the source voltage is lost as heat along the cable path. Using Ohm's law (V = I × R) and circular-mil resistivity at 75°C, the voltage lost across a two-wire circuit is:

VD=2 · K · I · LCM
(Single-phase / DC)
% Drop=VDVsource · 100%
(Percentage loss)

where:

  • VD – Total voltage drop between the supply panel and the load terminals, measured in volts (need a target gauge instead? Use the wire size calculator);
  • K – Conductor resistance constant at 75°C (K = 12.9 for copper and K = 21.2 for aluminum in Ω·CM/ft);
  • I – Load current flowing through the circuit in amps (estimate from wattage with our watts to amps calculator);
  • L – One-way wire distance in feet (the multiplier of 2 already accounts for the return conductor); and
  • CM – Conductor cross-sectional area in circular mils from NEC Chapter 9, Table 8.

Three-phase AC voltage drop equation

In a balanced three-phase system, the return currents cancel in phase opposition, so the round-trip factor of 2 is replaced by √3:

VD3Φ=√3 · K · I · LCM
(Balanced 3-phase)

Subtract VD from the source voltage (V_load = V_source − VD) to find the actual voltage delivered to the equipment terminals. Explore all related tools in our electrical calculators hub.

Worked example: 120 V, 20 A, 75 ft, 12 AWG copper

Simplified resistance-based calculation.
StepCalculationResult
Volts lost2 × 12.9 × 20 × 75 ÷ 6,5305.93 V
Percentage5.93 ÷ 120 × 1004.94%
Load voltage120 − 5.93114.1 V

What changes the result

  • Double current and volts lost doubles
  • Double distance and volts lost doubles
  • Use a larger circular-mil area and volts lost decreases
  • Use a lower source voltage and the same volts lost becomes a larger percentage
  • Change conductor material and the K constant changes

Use real operating inputs

Nameplate or calculated design current is more useful than an arbitrary breaker value. Sensitive equipment, motors and circuits with distributed loads may need a method beyond the simple lumped-current formula.

Formula guide or calculator?

Use this page when you want to check each equation step. Use the single-phase voltage drop calculator when you need an interactive estimate for a chosen AWG, voltage, current, material and distance.

Keeping these jobs separate prevents the formula article from pretending to be another calculator page: this guide explains the method, while the calculator compares live inputs and output voltage.

Single phase compared with balanced three phase

Input convention for the site's simplified resistance models.
CircuitMultiplierVoltage inputDistance input
DC / single phase2Source voltageOne-way
Balanced three phase√3Line-to-lineOne-way

Frequently asked questions

Why does the single-phase formula multiply by 2?

The factor of two represents the outgoing and return conductor path when the entered distance is one-way.

Should I enter one-way or round-trip distance?

Enter one-way source-to-load distance. Do not double it before using the formula because the factor of two already accounts for the return path.

How do I find estimated load voltage?

Subtract calculated volts lost from source voltage. For example, a 5.93 V loss from 120 V leaves about 114.1 V.

What is the load voltage formula?

Estimated load voltage equals source voltage minus calculated voltage drop. In this simplified single-phase model, calculate voltage drop as 2 × K × current × one-way distance divided by conductor circular-mil area.

Does this formula select a safe wire size?

No. It estimates voltage drop only. A qualified professional must still verify load, ampacity, protection, terminals, adjustment factors and the installation method.